33r^2+47r-70=0

Solution for 33r^2+47r-70=0 equation:

33r^2+47r-70=0

a = 33; b = 47; c = -70;
Δ = b2-4ac
Δ = 472-4·33·(-70)
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-107}{2*33}=\frac{-154}{66}
=-2+1/3
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+107}{2*33}=\frac{60}{66}
=10/11
$